a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)

   =1

b)=(1.2.3....8).(9-1-8)

   =(1.2.3....8).0

   =0

mik chỉ giải được zậy thôi.

t mik nha.

(10*2+11*2+12*2):(13*2+14*2)=100+121+144):(169+196)=1

a) Đặt \(A=\left(10^2+11^2+12^2\right)\div\left(13^2+14^2\right)\)

- Ta có: \(A=\left(100+121+144\right)\div\left(169+196\right)\)

      \(\Leftrightarrow A=365\div365=1\)

Vậy \(A=1\)

b) Đặt \(B=1.2.3.....9-1.2.3.....8-1.2.3.....8^2\)

- Ta có: \(B=1.2.3.....8.\left(9-1\right)-1.2.3.....8^2\)

     \(\Leftrightarrow B=1.2.3.....8.8-1.2.3.....8.8=0\)

Vậy \(B=0\)

c) Đặt \(C=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

- Ta có: \(C=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

      \(\Leftrightarrow C=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)

      \(\Leftrightarrow C=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)

      \(\Leftrightarrow C=\frac{9.2^{36}}{2^{35}.9}\)

      \(\Leftrightarrow C=2\)

Vậy \(C=2\)

d) Đặt \(D=1152-\left(374+1152\right)+\left(-65+374\right)\)

- Ta có: \(D=1152-374-1152-65+374\)

      \(\Leftrightarrow D=\left(1152-1152\right)+\left(374-374\right)-65\)

      \(\Leftrightarrow D=-65\)

Vậy \(D=-65\)

a: \(\dfrac{10^2+11^2+12^2}{13^2+14^2}=\dfrac{100+121+144}{169+196}=\dfrac{365}{365}=1\)

c: \(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot\left(11-2\right)}=2\)

Câu 1 dễ mà :

1.2.3...9 - 1.2.3...8 - 1.2.3...7.8²

= 1.2.3...8.9 - 1.2.3...8.1 - 1.2.3...7.8.8

= 1.2.3...8.( 9 - 1 - 8 )

= 1.2.3...8.0

= 0

còn câu 2 và 3 thì sao

K ghi lại đề câu 2 nha :

\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^{36}}{11.2^{35}-2^{35}.2}\)

\(=\frac{3^2.2^{36}}{2^{35}\left(11-2\right)}\)

\(=\frac{3^2.2^{36}}{2^{35}.3^2}\)

\(=\frac{3^2}{3^2}.\frac{2^{36}}{2^{35}}\)

\(=1.2=2\)

a,(10^2+11^2+12^2):(13^2+14^2)

=(100+121+144);(169+196)

=365:365

=1

b,1.2.3...9-1.2.3...8-1.2.3...8^2=0

a)=(100+121+144):(169+196)=365:365=1

b)=1.2.3...8.(9-1-8)=1.2.3...8.0=0

k mk nhaa